RS Aggarwal Quantitative Aptitude PDF Free Download: TABULATION

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TABULATION

This section comprises of questions in which certain data regarding common disciplines as production over a period of a few years: imports, exports, incomes of employees in a factory, students applying for and qualifying a certain field of study etc. are given in the form of a table. The candidate is required to understand the given information and thereafter answer the given questions on the basis of comparative analysis of the data.

Thus, here the data collected by the investigator are arranged in a systematic form in a table called the tabular form. In order to avoid some heads again and again, tables are made consisting of horizontal lines called rows and vertical lines called columns with distinctive heads, known as captions. Units of measurements are given with the captions.

 

 SOLVED EXAMPLES

 

 

 The following table gives the sales of batteries manufactured by a company lit the years. Study the table and answer the questions that follow:

                                                                                (S.B.I.P.O. 1998)

NUMBER OF DIFFERENT TYPES OF BATTERIES SOLD BY A COMPANY OVER THE YEARS (NUMBERS _N THOUSANDS)

 

TYPES OF BATTERIES

Year

 

4AH

 

7AH

 

32AH

35AH

55AH

T0TAL

1992

75

144

114

102

108

543

 

1993

90

126

102

84

426

528

 

1994

96

114

75

105

135

525

1995

105

90

150

90

75

510

1996

90

75

135

75

90

465

1997

105

60

165

45

120

495

1998

115

85

160

100

145

605

 

 

  1. The total sales of all the seven years is the maximum for which battery ?

    (a) 4AH            (b) 7AH           (c) 32AH           (d) 35AH         (e) 55AH

  1. What is the difference in the number of 35AH batteries sold in 1993 and 1997 ?

    (a) 24000         (b) 28000        (c) 35000           (d) 39000        (e) 42000

  1. The percentage of 4AH batteries sold to the total number of batteries sold was maximum in the year:

    (a) 1994       .   (b) 1995           (c) 1996            (d) 1997         (e) 1998

  1. In the case of which battery there was a continuous decrease in sales from 1992 to 1997 ?

    (8) 4AH            (b) 7 AH            (c) 32AH            (d) 35AH            (e) 55AH

  1. What was the approximate percentage increase in the sales of 55AH batteries in 1998 compared to that in 1992 ?

    (a) 28%            (b) 31%            (c) 33%                (d)34%            (e)37%

 

Sol. 1. (c) : The total sales (in thousands) of all the seven years for various batteries are:

For 4AH = 75 + 90 + 96 + 105 + 90 + 105 + 115 = 676

For  7AH = 144 + 126 + 114 + 90 + 75 + 60 + 85 = 694

For 32AH = 114 + 102 + 75 + 150 + 135 + 165 + 160 = 901

For 35 AH= 102 + 84 + 105 + 90 + 75 + 45 + 100 = 601

 For 55 AH= 108 + 126 + 135 + 75 + 90 + 120 + 145 = 799.

Clearly, sales are maximum in case of 32AH  batteries.

  1. (d\ : Required difference = [(84 – 45) x 1000] = 39000.
  2. (d) : The percentages of sales of 4AH batteries to the total sales in different years are:

           For 1992 =(75*100/543)%=13.81%

           For 1993=(90*100)/528%=17.05%

           For 1994=(96*100/465)%=19.35%

           For 1995=(105*100/495)%=20.59%

           For 1996=(96*100/465)%=19.35%

           For 1997=(105*100/495)%=21.21%

           For 1998=(115*100/605)%=19.01%

           Clearly, the percentage is maximum in 1997.

  1. (b) : From the table it is clear that the sales of 7AH batteries have been decreasing continuously from 1992 to 1997.
  2. (d) : Required Percentage =(145-108)/108)*100 %=34.26%=34%.

 

Ex 2: Study the following table carefully  and answer these questions:

 

NUMBER OF CANDIDATES  APPEARED AND QUALIFIED IN A COMPETITIVE EXAMINATION  FROM  DIFFERENT  STATES  OVER  THE   YEAR                                                                                                                      

 

 

1997

1998

1999

2000

2001

 

App.

Qual.

App.

Qal.

App.

Qual.

App.

Qual.

App.

Qual

M

5200

720

8500

980

7400

850

6800

775

9500

1125

N

7500

840

9200

1050

8450

920

9200

980

8800

1020

P

6400

780

8800

1020

7800

890

8750

1010

9750

1250

Q

8100

950

9500

1240

8700

980

9700

1200

8950

995

R

7800

870

7600

940

9800

1350

7600

945

7990

885

 

  1. Combining the states P and Q, together in 1998, what is the percentage of the candidates qualified to that of the canditates appeared?

    (8) 10.87% (b) 11.49%      (c) 12.35%  (d) 12.54%   (e) 13.50%

 

   2.The percentage of the total number of qualified candidates to the total number appeared candidates among all the five states in 1999 is :

    (a) 11.49% (b) 11.84%      (c)- 12.21% (d) 12.57% (e) 12.7a1

 

  1. What is the percentage of candidates qualified from State N for all the years together, over the candidates appeared from State N during all the years together?

    (a) 12.36% (b) 12.16% (c) 11.47% (d) 11.15% (e)None of these

 

  1. What is the average of candidates who appeared from State Q during the given yeas?

   (8) 8700       (b) 8760        (c) 8810        (d) 8920        (e) 8990

 

   5 . In which of the given years the number of candidates appeared from State P has maximum percentage of qualified candidates?

   (8) 1997       (b) 1998        (c) 1999        (d) 2000        (e) 2001

 

  1. Total number of candidates qualified from all the states together in 1997 is approximately what percentage of the total number of candidates qualified from all the states together in 1998 ?

   (8) 72%        (b) 77%         (c) 80%        (d) 83%         (e) 86%

Sol.1.(c)Required  Percentage=(1020+1240) *100%=(2260*100)/18300%

                                         (8800+9500)

                                                       =12.35%

             Required  Percentage=   (850+920+890+980+1350) *100%

                                                     (7400+8450+7800+8700+9800)

                                                =(4990*100)/42150%

                                                =11.84%

         (e) : Required Percentage=(84-+1050+920+980+1020)/(7500+9200+8450+9200+8800)*100%

                                               =(4810*100)/43150* %

                                               =11.15%

  1. (e) Required average =(8100+9500+8700+9700+8950)/5

                                               =44950/5

                                               =8990

  1. (e) : The percentages of candidates qualified to candidates appeared from State P during different years are:

 

For 1997= 780  * 100% =12.19%

                 6400

for 1998 = 1020*100   %=11.59%

                      8800

 

For 1999 = 890*100   %=11.41%;

                     7800

 

 

For 2000 = 1010* 100 % = 11.54%.         

                     8 750

For 2001=1250*100 %=    12.82%

                     9750

          :. Maximum percentage is for the year 2001.

  1. (c) : Required Percentage =( 720 + 840 + 780 + 950 + 870) . x 100

                                                    980+1050+1020+1240+940

                                               =80%  

Ex. 3. The following  table gives the percentage of marks obtained by seven students in six , different subjects in an examination. Study the table and answer the questions based on it. The numbers in the brackets give the maximum marks in each subject.

(Bank P.O. 2003)

 

 

\

 

 

 

 

 

 

I

(Max.

Maths

Chemistry

Physics

Geography

History

Computer

 

   marks)

 

 

 

 

 

Science

 

Student

(160)

(130)

(120)

(100)

(60)

(40)

 

Ayush

90

50

90

60

70

80

 

Aman

100

80

80

40

80

70

 

Sajal

90

60

70

70

90

70

 

Rohit

80

65

80

80

60

60

 

Muskan

80

65

85

95

50

90

 

Tanvi

70

75

65

85

40

60

 

Tharun

65

35

50

77

80

80

 

 

  1. What was the aggregate of marks obtained by Sajal in all the six subjects?

     (a) 409         (b) 419           (c) 429          (d) 439          (e) 449

  1. What is the overall percentage of Thrun?

     (a) 52.5%    (b) 55%           (c) 60%         (d) 63%         (e) 64.5%

  1. What are the average marks obtained by all the seven students in Physics? (rounded off to two digits after decimal)

     (a) 77.26    (b) 89.14          (c) 91.37       (d) 96.11       (e) 103.21

  1. The number of students who obtained 60% and above marks in all the subjects is :

     (a) 1            (b) 2            (c) 3            (d) None        (e) None of these

  1. In which subject is the overall percentage the best?

     (a) History (b) Maths (c) Physics       (d) Chemistry  (e) Geography

Sol. 1.. (e) : Aggregate marks obtained by Sajal

= [(90% of 150) + (60% of 130) + (70% of 120) + (70% of 100) +

    (90% of 60)  + (70% of 40)] = 135 + 78 + 84 + 70 + 54 + 28 = 449.

  1. (c) : Aggregate marks obtained by Tarun .

= [(65% of 150) + (35% of 130) + (50% of 120) + (77% of 100) + (80% of 60) + (80% of 40)] = 97.5 + 45.5 + 60 + 77 + 48 + 32 = 360.

Total maximum marks (of all the six subjects)

= (150 + 130 + 120 + 100 + 60 + 40) = 600.

 

Overall percentage of Tarun = 360 x 100 % = 60%.

                                    .              600

  1. (b) : Average marks obtained in Physics by all the seven students

 

= 1 [(90% of 120) + (80% of 120) + (70% of 120) + (80% of 120)

   7        

         + (85% of 120) + (65% of 120) + (50% of 120)]

 

1 [(90 + 80 + 70 +80 + 85 + 65 + 50)% of 120]

    7         

 

=1 [520% of 120] = 89.14.

  7         

  1. (b) : From the table it is clear that Sajal and Rohit have 60% or more marks

in each of the six subjects.

  1. (b) : We shall find the overall percentage (for all the seven students) with respect to each subject.

The overall percentage for any subject is equal to the average of percentages obtained by all the seven students since the maximum marks for any subject is the same for all the students.

Therefore, overall percentage for:

(i) Maths = [1(90+100+90+80+80+70+65)]%

         7

= [1(575)]% = 82.14%.

       7

(ii) Chemistry = [1(50 + 80 + 60 + 65 + 65 + 75 + 35)]%

                               7

= [1(430)]% = 61.43%.                                            .

    7

(iii) Physics = [1(90 + 80 + 70 + 80 + 85 + 65 + 50)]%

                       7

                   =[1 (520)]% = 74.29%.

                      7

(iv) Geography = [1(60 + 40 + 70 + 80 + 95 + 85 + 77)]%

                            7       

                            = [1 (507)}_ = 72.43%.

                             7

(v) History = [1 (70 + 80 + 90+ 60 + 50 + 40 + 80)]%

                        7           

                     =1 [(470)]% = 67.14%.

                    7

(vi) Computer Science = [1/7 (80 + 70 + 70 + 60 + 90 + 60 + 80)]%

 

= [1 (510)]% = 72.86%.

     7   

Clearly; this. percentage is highest for Maths.

ex.4. Study the following table carefully and answer tbe questions given below:(Bank P.O. 2001)

CLASSIFICATION OF 100 STUDENTS BASED ON THE MARKS OBTAINED BY THEM IN PHYSICS AND CHEMISTRY IN AN EXAMINATION

 

Marks out

 

 

 

 

 

Of 50

40 and

30 and

20 and

10 and

0 and

Subject

above

Above

above

above

above

physics

9

32

80

92

100

 

 

 

 

,.

 

chemistry

4

,21

66

81,

100

(aggregate

 

 

 

 

 

Average)

7

27

73

87

100

 

  1. The number of students scoring less than 40% marks in aggregate is :

   (a) 13          (b) 19              (c) 20             (d) 27              (e) 34

  1. If at least 60% marks in Physics are required for pursuing higher studies in Physics,how many students will be eligible to pursue higher studies in Physics?

   (a) 27          (b) 32              (c) 34             (d)41               (e) 68

  1. What is the difference between the number of students passed with 30 as cut-off marks in Chemistry and those passed with :JUas cut-off marks in aggregate?

  (a) 3        (b) 4           (c) 5           (d) 6           (e) 7

 

  1. The percentage of the number of students getting at least 60% marks in Chemistry over those getting at least 40% marks in aggregate, is approximately:

  (a) 21%       (b) 27%        (c) 29%      (d) 31%    (e) 34%

  1. If it is known that at least 23 students were eligible for a Symposium on Chemistry the minimum qualifying marks in Chemistry for eligibility to Symposium would lie in the range:

       (a) 40-50 (b) 30-40     (c) 20-30     (d) Below 20

 

Sol. 1. (d) : We have 40% of 50 =(40 x 50)= 20.

                                                       100

           :. Required number = Number of students scoring less than 20 marks

                                             in   aggregate

                                            = 100 – number of students scoring 20 and above

                                              marks in aggregate = 100 – 73 = 27.

  1. (b) : We have 60% of 50 =(60 x 50) = 30.

                                                   100

:. Required number = Number of students scoring 30 and above mark

                                   in Physics = 32.                            .

  1. (d) : Required difference = (Number of students scoring 30 and above in mark in Chemistry) (Number of students scoring 30 and

          .                 above marks in aggregate) = 27 – 21 = 6.

  1. (c) : Number of students getting at least 60% marks in Chemistry

= Number of students getting 30 and above marks in Chemistry = 21. Number of students getting at least 40% marks in aggregate

= Number of students getting 20 and above marks in aggregate = 73.

:. Required Percentage = (21x 100)% = 28.77% ≈29%.

                                                  73

  1. (c) : Since 66 students get 20 and above marks in Chemistry and out of these 21 students get 30 and above marks, therefore to select top 35 students in Chemistry, the qualifying marks should lie in the range 20-30.

 

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